[vox-tech] Bash question

[Mitch Patenaude]

I'm also not sure if I understand what you want, but here's my best 
guess.

When invoked "inline" (with a .  at the beginning of a line), I don't
think you can get at the path name, but here are a couple of 
alternatives

## .bashrc
export MYAPPHOME=/opt/myapp
. $MYAPPHOME/bin/config

## /opt/myapp/bin/config
echo $MYAPPHOME
pushd $MYAPPHOME
   # whatever
popd


or alternatively:

## .bashrc
export MYAPPCONFIG=/opt/myapp/bin/config
export MYAPPHOME=`/usr/bin/dirname $MYAPCONFIG`/..
. $MYAPPCONFIG

## /opt/myapp/bin/config  is the same...



On Monday, Sep 29, 2003, at 05:18 US/Pacific, Jay Strauss wrote:

> Hi,
>
> I want to get the path of the file from a script called from .bashrc.  
> Like:
>
> ##.bashrc
> . /opt/myapp/bin/config
>
>
> ## /opt/myapp/bin/config
> pwd
> echo $0
>
>
> In this case during login:
> pwd = /home/jstrauss
> $0 = -bash
>
> I'd like to get a variable with the value /opt/myapp/bin/config
> but I can't find a combination of commands that will give my that 
> during
> login or su
>
> Jay
>
>
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