[vox-tech] perl question - arrays and lists

[Foo Lim]

\($foo, $bar)

is equivalent to

(\$foo, \$bar)

so you would be pushing to references to scalars onto the list and not a 
reference to a list.  (Not to mention I don't like being pushed around.  
(; )

Foo


On Thu, 8 May 2003, Michael Wenk wrote:

> On Thursday 08 May 2003 01:53 pm, Jay Strauss wrote:
> > you need push @array, [$foo, $bar];
> 
> Here's a silly question, wouldn't: 
> 
> push @array, \($foo,$bar);  
> 
> work?  
> 
> Mike
> 
> >
> > ----- Original Message -----
> > From: "Peter Jay Salzman" <p@dirac.org>
> > To: <vox-tech@lists.lugod.org>
> > Sent: Thursday, May 08, 2003 3:12 PM
> > Subject: [vox-tech] perl question - arrays and lists
> >
> > > there's some code i wrote that does something like:
> > >
> > > sub blah()
> > > {
> > >    foreach (@foobar)
> > >    {
> > >       push @array, ($foo, $bar);
> > >    }
> > >
> > >    return @array;
> > > }
> > >
> > > so i'm returning an array whose elements are each a list of two items.
> > > the receiving code is something like:
> > >
> > >    my @barfoo = blah();
> > >
> > > what i've found is that @barfoo is no longer an array of lists.  the
> > > lists appear to be "flattened out".
> > >
> > > so in the previous example, if there's one element of @foobar and $foo
> > > is "hello" and $bar is "dolly", then what i see is:
> > >
> > >    $barfoo[0] is "hello";
> > >    $barfoo[1] is "dolly";
> > >
> > > when what i really want is;
> > >
> > >    $barfoo[0] = ("hello", "dolly");
> > >
> > > i know that arrays can hold lists, but i must not be doing it correctly.
> > > do i need to do this with references?
> > >
> > > pete
> > >
> > > --
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